发布于2023-05-25 21:18 阅读(1149) 评论(0) 点赞(27) 收藏(4)
So I was wondering how can we access a model which is placed in a variable
Controller :
use App\Models\Test;
use App\Models\Owner;
class mainController extends Controller {
public function __construct()
{
$this->home = new MainHelper();
}
mainHelper.php :
class MainHelper {
var $test = 'App\Models\Test';
...
public static function listTesting(){
$data = $this->test::where('icons_status', '=', 'active')->orderBy('created_at', 'desc')->take(5)->get();
return $data;
}
Test.php
<?php
namespace App\Models;
use Illuminate\Database\Eloquent\Model;
class Test extends Model
{
protected $table = 'test';
protected $primaryKey = "id";
protected $guarded = array('id');
public $timestamps = false;
}
But I get this error
Parse error: syntax error, unexpected '::' (T_PAAMAYIM_NEKUDOTAYIM) in C:\xampp\htdocs\laravel\app\Helpers\MainHelper.php on line 34
Or am I doing it wrong? I'm trying to find a way without using use App\Model\Test
First of all, why do you want to assign a model into a variable?, Second of all, in this line:
var $test = 'App\Models\Test';
you are assigning a String, not a Model, so obviously is not going to work as you expected.
What you can do is:
var $test = new App\Models\Test;
and then use
var $test->where(....)
or do it in the same instruction:
$data = App\Models\Test::where('icons_status', '=', 'active')->orderBy('created_at', 'desc')->take(5)->get();
return $data;
作者:黑洞官方问答小能手
链接:http://www.phpheidong.com/blog/article/546122/325c646f103367a9cd35/
来源:php黑洞网
任何形式的转载都请注明出处,如有侵权 一经发现 必将追究其法律责任
昵称:
评论内容:(最多支持255个字符)
---无人问津也好,技不如人也罢,你都要试着安静下来,去做自己该做的事,而不是让内心的烦躁、焦虑,坏掉你本来就不多的热情和定力
Copyright © 2018-2021 php黑洞网 All Rights Reserved 版权所有,并保留所有权利。 京ICP备18063182号-4
投诉与举报,广告合作请联系vgs_info@163.com或QQ3083709327
免责声明:网站文章均由用户上传,仅供读者学习交流使用,禁止用做商业用途。若文章涉及色情,反动,侵权等违法信息,请向我们举报,一经核实我们会立即删除!