发布于2023-01-19 16:51 阅读(982) 评论(0) 点赞(18) 收藏(1)
In my application users creating articles and adding images to it if user wont add a image, that application must search for it in google images and add that image to user article. But when i tried to get image from google. Im get this error:
AbstractDecoder.php line 302:
Image source not readable
Controller Method:
public function store(ArticleRequest $request)
{
if ($request->hasFile('file')) {
$file = Input::file('file');
$imgTitle = $request->title;
$imagePath = 'uploads/' . $imgTitle . '.jpg';
$request->image_path = $imagePath;
Article::create(array('title' => $request->title,
'body' => $request->body,
'image_path' => $imagePath));
Image::make($file)->resize(300, 200)->save($imagePath);
} else {
// $file = Input::file('file');
$imgTitle = $request->title;
$query = $imgTitle;
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=" . urlencode($query));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$output = json_decode(curl_exec($ch));
// $file = file_get_contents($output);
curl_close($ch);
$imagePath = 'uploads/' . $imgTitle . '.jpg';
$request->image_path = $imagePath;
Article::create(array('title' => $request->title,
'body' => $request->body,
'image_path' => $imagePath));
Image::make($output)->resize(300, 200)->save($imagePath);
}
}
$output = json_decode(curl_exec($ch));
Returns a json object with the results. If you want to get the first image url add
$output = json_decode(curl_exec($ch));
if(!empty($responseData->results))
$output = $output->responseData->results[0]->url;
else {
die('no image found');
}
作者:黑洞官方问答小能手
链接:http://www.phpheidong.com/blog/article/476831/c89d0b0baf2101ad35f1/
来源:php黑洞网
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